Extract | Total glucana | α-glucanb | β-glucanc | Proteind | Phenolic acide |
---|
P. giganteus HAE | 27.6 ± 0.2 | 17.6 ± 0.1 | 10.1 ± 0.1 | 18.2 ± 2.3 | 0.33 ± 0.01 |
P. giganteus ASE | 31.6 ± 0.4 | 3.5 ± 0.3 | 28.1 ± 0.5 | 12.6 ± 0.9 | 0.18 ± 0.01 |
L. rhinocerotis HAE | 71.8 ± 4 | 13.5 ± 1.1 | 58.4 ± 1.1 | 16.5 ± 2.5 | 0.32 ± 0.06 |
L. rhinocerotis ASE | 23.4 ± 0 | 7.8 ± 0.3 | 15.6 ± 0.3 | 27.6 ± 0.4 | 0.25 ± 0.03 |
S. communae HAE | 4.8 ± 0.3 | 0.2 ± 0 | 4.6 ± 0.3 | 18 ± 1.9 | 0.33 ± 0.06 |
S. communae ASE | 35.8 ± 0.3 | 1.4 ± 0.1 | 34.4 ± 0.4 | 15 ± 0.4 | 0.31 ± 0.05 |
H. erinaceus HAE | 2.0 ± 0 | 0.5 ± 0.1 | 1.6 ± 0.1 | 20.6 ± 1.7 | 0.32 ± 0.06 |
H. erinaceus ASE | 2.9 ± 1.7 | 0.3 ± 0.1 | 2.7 ± 0.1 | 12.7 ± 0.8 | 0.2 ± 0.02 |
G. lucidium HAE | 9.4 ± 1.3 | 4.5 ± 0.4 | 4.9 ± 1.8 | 22 ± 3.7 | 1.28 ± 0.16 |
G. lucidium ASE | 11.1 ± 0 | 1.3 ± 0.1 | 9.8 ± 0.1 | 19 ± 1.9 | 0.73 ± 0.08 |
- Percentages of α-glucan, β-glucan, protein, phenolic content in 10 mg/ml mushroom extracts were calculated as the mean ± standard deviation of three independent experiments using the formula listed below:
- aTotal glucan: \( \mathrm{Absorbance}\times \frac{100\ \left(\upmu \mathrm{g}\ \mathrm{of}\ \mathrm{the}\ \mathrm{D}\hbox{-} \mathrm{g}\mathrm{lucose}\ \mathrm{standard}\right)}{\mathrm{GOPOD}\ \mathrm{absorbance}\ \mathrm{for}\ 100\;\upmu \mathrm{g}\ \mathrm{of}\ \mathrm{D}\hbox{-} \mathrm{g}\mathrm{lucose}\ \mathrm{standard}}/\mathrm{weight}\ \mathrm{of}\ \mathrm{sample}\times 90 \)
- bα-glucan: \( \mathrm{Absorbance}\times \frac{100\ \left(\upmu \mathrm{g}\ \mathrm{of}\ \mathrm{the}\ \mathrm{D}\hbox{-} \mathrm{g}\mathrm{lucose}\ \mathrm{standard}\right)}{\mathrm{GOPOD}\ \mathrm{absorbance}\ \mathrm{for}\ 100\;\upmu \mathrm{g}\ \mathrm{of}\ \mathrm{D}\hbox{-} \mathrm{g}\mathrm{lucose}\ \mathrm{standard}}/\mathrm{weight}\ \mathrm{of}\ \mathrm{sample}\times 9.27 \)
- cβ-glucan: Total glucan – α-glucan
- dTotal protein content estimated from the bovine serum albumin standard curve (Absorbance at 595 nm = 0.001 (concentration of protein) - 0.166). % protein: concentration of protein (mg)/concentration of extract (10 mg) × 100
- eTotal phenolic content estimated from the gallic acid standard curve (Absorbance at 650 nm = 0.939 {concentration of phenolic (mM)} - 0.055). % phenolic: concentration of phenolic (mM) × 170/conc of extract (10 mg) × 100